Palindromic numbers n(n + a)

To find n such that n(n + a) is a Palindromic number

a = 1, 2, 3, 4, 5, 6, 7, 8, 9

n(n + 1)

n(n + 2)

n(n + 3)

n(n + 4)

n(n + 5) ... 814 * (814 + 5) = 666666.

n(n + 6)

n(n + 7)

n(n + 8)

n(n + 9)


n(n + 20) ... 23 * (23 + 20) = 989